python - Find the index of a list of tuples with nondistinct values in first index of tuple -


i'm trying index of list of 2-tuples in python, 0 index of each tuple 'a':

list_of_tuples = [('a', 1), ('a', 2), ('a', 3)]

so use following list comprehension try find out index returned, correct?

index_list = [x x, y in enumerate(list_of_tuples) if x[0] == 'a']

which gives following error: 

typeerror                                 traceback (most recent call last) <ipython-input-22-5d47328b7d9a> in <module>() ----> 1 index_list = [x x, y in enumerate(list_of_tuples) if x[0] ==     'a']  typeerror: 'int' object not subscriptable

how find out index associated searching list of tuples value in 0th index being equal 'a'?

use value y compare not index x:

list_of_tuples = [('a', 1), ('a', 2), ('a', 3)] index_list = [x x, y in enumerate(list_of_tuples) if y[0] == 'a']

now index_list [0, 1, 2].


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