python - How can I strip namespaces out of an lxml tree? -


following on removing child elements in xml using python ...

thanks @tichodroma, have code:

if can use lxml, try this:

 import lxml.etree   tree = lxml.etree.parse("leg.xml")  dog in tree.xpath("//leg1:dog",                        namespaces={"leg1": "http://what.not"}):      parent = dog.xpath("..")[0]      parent.remove(dog)      parent.text = none  tree.write("leg.out.xml")

now leg.out.xml looks this:

 <?xml version="1.0"?>  <leg1:mor xmlns:leg1="http://what.not" ocount="7">    <leg1:order>      <leg1:ctemp id="fo">        <leg1:group bnum="001" ccount="4"/>        <leg1:group bnum="002" ccount="4"/>      </leg1:ctemp>      <leg1:ctemp id="go">        <leg1:group bnum="001" ccount="4"/>        <leg1:group bnum="002" ccount="4"/>      </leg1:ctemp>    </leg1:order>  </leg1:mor>

how modify code remove leg1: namespace prefix of elements' tag names?

one possible way remove namespace prefix each element :

def strip_ns_prefix(tree):     #iterate through element nodes (skip comment node, text node, etc) :     element in tree.xpath('descendant-or-self::*'):         #if element has prefix...         if element.prefix:             #replace element name it's local name             element.tag = etree.qname(element).localname     return tree

another version has namespace checking in xpath instead of using if statement :

def strip_ns_prefix(tree):     #xpath query selecting element nodes in namespace     query = "descendant-or-self::*[namespace-uri()!='']"     #for each element returned above xpath query...     element in tree.xpath(query):         #replace element name it's local name         element.tag = etree.qname(element).localname     return tree

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