python 2.7 - How to stop recursive function before index out of range? -
def isincreasing(ls): if not ls: print "list empty or short" return return (false if ls[0] > ls[1] else isincreasing(ls[1:])) i have made check if list sorted. how can make function stop when there no more check? im getting error "list index out of range". just add: checking if 2 elements in list checking if 1 element or no element in list code: def isincreasing(ls): if len(ls) < 2: print "list empty or short" return if len(ls) == 2: return ls[0] < ls[1] return (false if ls[0] > ls[1] else isincreasing(ls[1:])) print "{}", isincreasing({}) print "[]", isincreasing([]) print [1,2,3], isincreasing([1,2,3]) print [4,6,8], isincreasing([4,6,8]) print [2,1,2,3], isincreasing([2,1,2,3]) print [1,2,3,2], isincreasing([1,2,3,2]) print [3,2,1], isincreasing([3,2,1]) output: {} list empty or short none [] list empty or short none [1, 2, 3] true [4, 6, 8] ...