python 2.7 - How to stop recursive function before index out of range? - 


def isincreasing(ls): if not ls:     print "list empty or short"     return return (false if ls[0] > ls[1] else isincreasing(ls[1:]))

i have made check if list sorted. how can make function stop when there no more check?

im getting error

"list index out of range".

just add:

  • checking if 2 elements in list
  • checking if 1 element or no element in list

code:

def isincreasing(ls):     if len(ls) < 2:         print "list empty or short"         return     if len(ls) == 2:         return ls[0] < ls[1]     return (false if ls[0] > ls[1] else isincreasing(ls[1:]))  print "{}", isincreasing({}) print "[]", isincreasing([]) print [1,2,3], isincreasing([1,2,3]) print [4,6,8], isincreasing([4,6,8]) print [2,1,2,3], isincreasing([2,1,2,3]) print [1,2,3,2], isincreasing([1,2,3,2]) print [3,2,1], isincreasing([3,2,1])

output:

{} list empty or short none [] list empty or short none [1, 2, 3] true [4, 6, 8] true [2, 1, 2, 3] false [1, 2, 3, 2] false [3, 2, 1] false

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