bash - What's wrong with this shell tests? -


in script has functions defined:

#!/bin/bash --  outtrue  (){ printf "%15s t|%s" "$*" "$?"; } outfalse (){ printf "%15s f|%s" "$*" "$?"; }  tval1(){  [ "$@" ]  && outtrue "$@" || outfalse "$@"; } tval2(){  [ "$*" ]  && outtrue "$@" || outfalse "$@"; } tval3(){ [[ "$@" ]] && outtrue "$@" || outfalse "$@"; }  tval(){     printf "test %s\t" "$1"; shift     case $1 in         (1) shift; tval1 "$@" ;;         (2) shift; tval2 "$@" ;;         (3) shift; tval3 "$@" ;;     esac     printf "\n" }

this tests work (as expected):

xyz="str";  tval "-n var"       1   "-n" "$xyz" xyz="str";  tval "-z var"       1   "-z" "$xyz" one=1;      tval "1 -eq \$one"  1   "1" "-eq" "$one" one=2;      tval "1 -eq \$one"  1   "1" "-eq" "$one"

results:

test -n var              -n str t|0 test -z var              -z str f|1 test 1 -eq $one         1 -eq 1 t|0 test 1 -eq $one         1 -eq 2 f|1

however, changing "$@" "$*" or using bash test [[...]] makes tests fail (note here either function 2 or 3 used) :

one=1;  tval "1 -eq \$one"  2   "1" "-eq" "$one" one=2;  tval "1 -eq \$one"  2   "1" "-eq" "$one"  one=1;  tval "1 -eq \$one"  3   "1" "-eq" "$one" one=2;  tval "1 -eq \$one"  3   "1" "-eq" "$one"

results:

test 1 -eq $one         1 -eq 1 t|0 test 1 -eq $one         1 -eq 2 t|0  test 1 -eq $one         1 -eq 1 t|0 test 1 -eq $one         1 -eq 2 t|0

do see problem?

the quoting!!

with "$*" , bash [[...]] command line values not split.

the tests equivalent [ word ] word not empty, , true.


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