linux - list the uniq lines based on ":" delimiter -


this question has answer here:

i trying write script find unique lines(first occurance) based on columns/delimiters. in case understanding delimiter ":".

for example:

may 14 00:00:01  server1 ntp[1006]:  ntpd[info]: 1430748797.780852: ndtpq.c(20544): log   may 14 00:00:01  server1 ntp[1006]:  ntpd[info]: 1430748797.780853: ndtpq.c(20544): log   may 14 00:00:02  server1 ntp[1006]:  ntpd[info]: 1430748798.780852: ndtpq.c(20544): log   may 14 00:00:03  server1 ntp[1006]:  ntpd[info]: 1430748799.780852: ndtpq.c(20544): log   may 14 00:00:04  server1 ntp[1006]:  ntpd[info]: 1430748800.780852: ndtpq.c(20544): log   may 14 00:00:04  server1 ntp[1006]:  ntpd[info]: 1430748800.790852: ndtpq.c(20544): log   may 14 00:00:05  server1 ntp[1006]:  ntpd[info]: 1430748801.790852: ndtpq.c(20544): thisis different log

desired output:

may 14 00:00:01  server1 ntp[1006]:  ntpd[info]: 1430748797.780852: ndtpq.c(20544): log   may 14 00:00:01  server1 ntp[1006]:  ntpd[info]: 1430748797.780853: ndtpq.c(20544): log   may 14 00:00:05  server1 ntp[1006]:  ntpd[info]: 1430748801.790852: ndtpq.c(20544): thisis different log

i able find uniq log using following command ,i loosing timestamp using way. 

cat filename |awk -f: '{print $7}'

this may do:

awk -f: '!seen[$nf]++' file may 14 00:00:01  server1 ntp[1006]:  ntpd[info]: 1430748797.780852: ndtpq.c(20544): log may 14 00:00:01  server1 ntp[1006]:  ntpd[info]: 1430748797.780853: ndtpq.c(20544): log may 14 00:00:05  server1 ntp[1006]:  ntpd[info]: 1430748801.790852: ndtpq.c(20544): thisis different log

it splits file using :, looks @ last field, , prints unique.


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