scala - Sort a list given a list of indices -


say have 1 unordered list

val unsorted = list("third", "second", "fourth", "first")

and have list has indices of above list in proper order

val ids = list(3, 1, 0, 2)

how can sort unsorted using these indices result

list("first", "second", "third", "fourth")

simply map ids onto unsorted list itself.

scala> val sorted = ids map unsorted.toindexedseq sorted: list[string] = list(first, second, third, fourth)

converting unsorted indexedseq not necessary, @gzm0 points out below prevents operation being o(n^2).


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