Bash script: variable output to rm with single quotes -


i'm trying pass parameter rm in bash script clean system automatically. example, want remove except *.doc files. wrote following codes. 

#!/bin/bash remove_target="!*.txt" rm $remove_target

however, output say

rm: cannot remove ‘!*.txt’: no such file or directory

it bash script add single quotes me when passing variable rm. how can remove single quotes?

using bash

suppose have directory 3 files

$ ls a.py  b.py  c.doc

to delete except *.doc:

$ shopt -s extglob $ rm !(*.doc) $ ls c.doc

!(*.doc) extended shell glob, or extglob, matches files except ending in .doc.

the extglob feature requires modern bash.

using find

alternatively:

find . -maxdepth 1 -type f ! -name '*.doc' -delete

-

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