Bash function to run or echo a string -


i've written bash script, creates lvm snapshots , works great. added function make dryrun, can see happen. this, script has several constructions this:

if [ $dryrun == "1" ];             echo "dryrun: lvcreate $snapshot_size -s -n $snapshotname \"$vg/$lv\""         else             lvcreate $snapshot_size -s -n $snapshotname "$vg/$lv"         fi

which awful. want refactor properly.

one way write function, expects string , function runs string command, if dryrun isn't set or prints out string (correctly escaped) if otherwise. however, have no idea how that.

how done? there other way improve code?

you use this:

run() {     if (( dryrun ));         printf "dryrun:"         printf ' %q' "$@"         printf '\n'     else        "$@"     fi }  dryrun=1 run echo "testing testing"

though note work simple commands. bashfaq 50 has more info on subject.

another way approach override important commands dryrun:

if (( dryrun ));     lvcreate() {         printf 'dryrun: %s' "${funcname[0]}"; printf ' %q' "$@"; printf '\n'     }     rm() {         printf 'dryrun: %s' "${funcname[0]}"; printf ' %q' "$@"; printf '\n'     }     fi

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