XSLT Transforming XML into a cross referenced, nested HTML lists when source nodes are siblings and nesting is based on attribute values -


problem: need create nested html unordered list xml not nested. additionally need cross reference xml 'allowed nodes' section contained in document.

example xml:

<content>   <data>     <navigation>       <link name="about us" url="#"/>       <link name="staff" url="staff.asp" parent="about us"/>       <link name="contact" url="contact.asp" parent="about us"/>       <link name="facebook" url="facebook.asp"/>     </navigation>   </data>   <allowedlinks>     <link name="about us"/>            <link name="facebook"/>   </allowedlinks> </content>

example result html (note have left out boiler plate code):

<ul>     <li>             <ul>         <li>staff</li>         <li>contact</li>       </ul>     </li>     <li>facebook</li> </ul>

ultimately form nav menu on site.

rules: -i need use xslt 1.0 create solution.

-if link exists, need add ul , create nested child ul's if siblings contain @parent of current nodes @name.

-before generating li item of node not have @parent, must first confirmed @name matches link @name in allowed links section.

in opinion - structure of xml being transformed stupid , makes transform process overly complex - since unable change original xml, need solution.

note - have answer works okay, post shortly. wanted see other possible answers first :)

bonus if can done template matching , not many each loops.

my solution contains 2 nested for-each's not like.

this classic case using keys:

xslt 1.0

<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/xsl/transform"> <xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/>  <xsl:key name="allowed-link" match="allowedlinks/link" use="@name" /> <xsl:key name="link-by-parent" match="link" use="@parent" />  <xsl:template match="/content">     <ul>         <xsl:apply-templates select="data/navigation/link[not(@parent) , key('allowed-link', @name)]"/>     </ul> </xsl:template>  <xsl:template match="link">     <li>         <xsl:value-of select="@name"/>         <xsl:variable name="sublinks" select="key('link-by-parent', @name)" />         <xsl:if test="$sublinks">             <ul>                 <xsl:apply-templates select="$sublinks"/>             </ul>         </xsl:if>     </li> </xsl:template>  </xsl:stylesheet>

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