Matlab identity shift matrix -


is there inline command generate shifted identity matrix in matlab?

a=[ ... 0, 1, 0, 0, 0, 0, 0, 0, 0, 0 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 0, 0, 0, 1, 0, 0, 0, 0, 0, 0 0, 0, 0, 0, 1, 0, 0, 0, 0, 0 0, 0, 0, 0, 0, 1, 0, 0, 0, 0 0, 0, 0, 0, 0, 0, 1, 0, 0, 0 0, 0, 0, 0, 0, 0, 0, 1, 0, 0 0, 0, 0, 0, 0, 0, 0, 0, 1, 0 0, 0, 0, 0, 0, 0, 0, 0, 0, 1 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

combination of circshift , eye needs command fix it. simpler way? (with 1 simple syntax)

try using diag call in combination ones. case, have 10 x 10 identity matrix , want shift diagonal right 1.

>> n = 10; >> shift = 1; >> = diag(ones(n-abs(shift),1),shift)  =      0     1     0     0     0     0     0     0     0     0    0     0     1     0     0     0     0     0     0     0    0     0     0     1     0     0     0     0     0     0    0     0     0     0     1     0     0     0     0     0    0     0     0     0     0     1     0     0     0     0    0     0     0     0     0     0     1     0     0     0    0     0     0     0     0     0     0     1     0     0    0     0     0     0     0     0     0     0     1     0    0     0     0     0     0     0     0     0     0     1    0     0     0     0     0     0     0     0     0     0

the above code works first declaring column vector of 1s, need n-abs(shift) of them moving right mean require less 1s fill things (more on later). n-abs(shift) corresponds total number of rows/columns of matrix , subtracting out many times shifting towards right. next, can use diag first parameter column vector creates zero matrix , places column vector coefficients along diagonal of matrix. second parameter (shift in case) allows offset place column. specifying positive value means move diagonals towards right, , in our case moving right shift, , hence our output results. truncating vector each position towards right moving, need decrease number of 1s in vector much.

up now, haven't explained why abs call shift required in last line of code. reason why abs call required accommodate negative shifts. if didn't have abs call in third line of code, n-shift adding more 1s vector , expand our matrix beyond n x n. because moving diagonals left decreases amount of 1s seen in result, that's why abs call required you'll notice shift constant left untouched in second parameter of diag.

here's demonstration negative shift, shift = -1, , still maintaining size 10 x 10:

a =       0     0     0     0     0     0     0     0     0     0      1     0     0     0     0     0     0     0     0     0      0     1     0     0     0     0     0     0     0     0      0     0     1     0     0     0     0     0     0     0      0     0     0     1     0     0     0     0     0     0      0     0     0     0     1     0     0     0     0     0      0     0     0     0     0     1     0     0     0     0      0     0     0     0     0     0     1     0     0     0      0     0     0     0     0     0     0     1     0     0      0     0     0     0     0     0     0     0     1     0

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