Return vector from a function C++ -

i trying return vector values in reverse order (e.g, enter vector 0,1,2,3,4 , function return vector 4,3,2,1,0).

the compiler says: segmentation fault.

in tests observed problem in assignment new2 = ret_vec(numbers);, don't know going on.

#include <string> #include <iostream> #include <vector>  using namespace std;  vector<int> ret_vec(vector<int>n){     vector <int> n2;      (int = 0; i< n.size(); ++i){         n2[i] = n[i];     }      return n2; }  void initializer(int s, vector<int>& n){      (int = 0; i< s; ++i){         n.push_back(i);     } }  void print_vector(vector<int> n){      (int = 0; i<n.size(); ++i){         cout << n[i] << " ";     } }  int main () {     vector <int> numbers;     int size;      cin >> size;     initializer(size,numbers);      vector <int> new2(numbers.size());      cout << "old ";     print_vector(numbers);      new2 =  ret_vec(numbers);      cout << "new ";     print_vector(new2);      return 0;  } 

in following function

vector<int> ret_vec(vector<int>n){     vector <int> n2;      (int = 0; i< n.size(); ++i){         n2[i] = n[i];     }      return n2; } 

you copy content of parameter vector. (i thing forgot space between parameter , typ of it)

you can revers order way, (its reverseit "by hand"):

vector<int> ret_vec(vector<int> n){     vector <int> n2;      for(int i=n1.size()-1; i<=0; --i)      {          n2.push_back(n1[i]);     }      return n2; }