How to insert record into two mysql table using php? -


i have 2 tables in database 1 "test1" , second "test2". , field test 1 "id","survey_no","lastname" , field of test have "id","survey_no","address" id test1 , test2 primary key , set auto-increment..what want here ever insert in "survey_no" in test1 should insert inserted in "survey_no in test2"..can please me it..please..

i have here code insertion called sample.php

<!doctype html public "-//w3c//dtd xhtml 1.0 transitional//en" "http://www.w3.org/tr/xhtml1/dtd/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>untitled document</title> </head>  <body>  <form method="post" class="signin" action="" name="add" id="form1"> <fieldset class="textbox">     <label class="province_id">         <span>province id</span>             <input id="province" name="survey_no" type="number" value="" autocomplete="on" placeholder="survey_no">     </label>     <label class="municipality">         <span>municipality</span>             <input id="municipality" name="lastname" value="" type="text" autocomplete="on" placeholder="lastname">     </label>     <br />     <br />     <button id="submit" type="submit" name="submit">save</button>     <button id="submit" type="reset" name="reset">reset</button>      </fieldset>       <?php     $conn=mysql_connect('localhost','root','');             if(!$conn)             {                 die('could not connect:' .mysql_error());             }             mysql_select_db("sample",$conn);      if(isset($_post['submit']))         {              $survey_no=$_post['survey_no'];             $lastname=$_post['lastname'];              $result = mysql_query("insert `test1`(survey_no,lastname)       values ('$survey_no','$lastname')");       if($result)     {     echo "<script type=\"text/javascript\">".     "alert('saved!');".     "</script>";     }     else{         echo "<script type=\"text/javascript\">".     "alert('failed!');".     "</script>";         }  }  ?>  </form>   </body> </html>

so far understand want this

$result = mysql_query("insert `test1`(survey_no,lastname)       values ('$survey_no','$lastname')");   $result1 = mysql_query("insert `test2`(survey_no)       values ('$survey_no')");

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